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Home/ Questions/Q 7406259
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T05:31:49+00:00 2026-05-29T05:31:49+00:00

I am using 2′ complement to represent a negative number in binary form Case

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I am using 2′ complement to represent a negative number in binary form

Case 1:number -5

According to the 2′ complement technique:

Convert 5 to the binary form:

00000101, then flip the bits

11111010, then add 1

00000001

=> result: 11111011

To make sure this is correct, I re-calculate to decimal:

-128 + 64 + 32 + 16 + 8 + 2 + 1 = -5

Case 2: number -240

The same steps are taken:

11110000

00001111

00000001

00010000 => recalculate this I got 16, not -240

I am misunderstanding something?

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  1. Editorial Team
    Editorial Team
    2026-05-29T05:31:49+00:00Added an answer on May 29, 2026 at 5:31 am

    The problem is that you are trying to represent 240 with only 8 bits. The range of an 8 bit signed number is -128 to 127.

    If you instead represent it with 9 bits, you’ll see you get the correct answer:

    011110000 (240)
    
    100001111 (flip the signs)
    +
    000000001 (1)
    
    =
    
    100010000
    
    =
    
    -256 + 16 = -240
    
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