Question

I am using a foreach to loop through image. There are maximum four images and minimum 1 image.
For example if there are two image (= two loops) i want to tell the foreach he needs to loop two times again and echo some placeholder pictures.

Heres my foreach:

<?php foreach($users as $k => $v) {?>
<img src="/images/user_<?php echo $k; ?>.jpg" alt="" title="" />
<?php } ?>

Outputs (two loops):

<img src="/images/user_0.jpg" alt="" title="" />
<img src="/images/user_1.jpg" alt="" title="" />

but the new script should output:

<img src="/images/user_0.jpg" alt="" title="" />
<img src="/images/user_1.jpg" alt="" title="" />
<img src="/images/user_placeholder.jpg" alt="" title="" />
<img src="/images/user_placeholder.jpg" alt="" title="" />

dont forget its possible that $users can have x entries (0-4)

Answer 1

Use array_fill to fill an array with as many items as needed (since they are all going to be identical) and then print them out.

<?php foreach($users as $k => $v) {?>
<img src="/images/user_<?php echo $k; ?>.jpg" alt="" title="" />
<?php } ?>

<?php
echo implode('', array_fill(0, count($users), 'placeholder image HTML'));

Of course instead of this cuteness you could also use another foreach that prints placeholder image HTML in each iteration.

Update: It turns out there’s an even better method:

echo str_repeat('placeholder image HTML', count($users));

PHP really has too many functions to remember. 🙂