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Home/ Questions/Q 8271313
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T06:48:24+00:00 2026-06-08T06:48:24+00:00

I am using a macro to open a file that the file name will

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I am using a macro to open a file that the file name will change each day because of the current date.

File\today_20120723 for today.

I am trying this but it isn’t working. Suggestions

Dim OpenPath As String
Dim OpenName As String

OpenPath = "N:\File\": OpenName = OpenPath & "today_" VBA.Format   (Date, "YYYYMMDD") & ".xlsx"



Workbooks.Open Filename:=OpenPath

Thanks for the help

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  1. Editorial Team
    Editorial Team
    2026-06-08T06:48:26+00:00Added an answer on June 8, 2026 at 6:48 am

    Multiple lines of code in a single line is really a pain to read.

    That said, I’m not sure what VBA.Format is doing in your code, but this should work:

    OpenPath = "N:\File\"
    OpenName = OpenPath & "today_" & Format(Date, "YYYYMMDD") & ".xlsx"
    
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