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Home/ Questions/Q 8977829
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T19:27:46+00:00 2026-06-15T19:27:46+00:00

I am using a member variable and at some point of the program I

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I am using a member variable and at some point of the program I want to change it, but i prefer to “lock it” everywhere else to prevent unintended changes.

Code to explain:

class myClass {
    int x;  // This should be prevented to being changed most of the time
    int y;  // Regular variable
    myclass() {x = 1;}
    void foo1 () {x++; y++;} // This can change x
    void foo2 () {x--; y--;} // This shouldn't be able to change x
                             // I want it to throw a compile error
};

The question is: Can it be achieved in some way? Something like permanent const_cast?

I know I could use constructor initialization list and constant right away, but i need to change my variable later.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T19:27:47+00:00Added an answer on June 15, 2026 at 7:27 pm

    Alright, all the other answers I dislike, so here’s my idea: hide the variable.

    #define READONLY(TYPE, VAR) const TYPE& VAR = this->VAR //C++03
    #define READONLY(VARIABLE) const auto& VARIABLE = this->VARIABLE //C++11
    
    class myClass {
        int x;  // This should be prevented to being changed most of the time
        int y;  // Regular variable
        myClass() :x(1), y(2) {}
        void foo1 () {// This can change x
            x++; 
            y++;
        } 
        void foo2 () {// This shouldn't be able to change x
            READONLY(x); //in this function, x is read-only
            x++; //error: increment of read-only variable 'x'
            y++;
        } 
    };
    

    There are still ways to bypass the locking of the variable (such as this->x), but nothing can be done for those situations.

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