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Home/ Questions/Q 7805039
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T02:05:44+00:00 2026-06-02T02:05:44+00:00

I am using a program to read keywords in a file and sort them

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I am using a program to read keywords in a file and sort them on basis of frequency. I am using Map data structure for the same.
But i am facing problem, even if i have repeated entries, their count is not increased. Thus if a word is repeated in the file it is stored in a different place in the data structure rather than incrementing value of the previous entry in the maps. Please find my code below. That is what i tried. Also i am making sure if a match is “” or ” ” it is not stored in the hash map still it is counted.

Pattern p = Pattern.compile("[a-zA-Z]*",Pattern.CASE_INSENSITIVE);
    Matcher m = p.matcher(handlerContent);
    while(m.find() ) //&& (m.group().length()>1)
    {
         boolean blnExists = keyword_counts.containsValue(m.group());
         if(blnExists==true)
         {
             if(m.group()!="" || m.group()!=" ")
             {
                 System.out.println("Repeat");
                 keyword_counts.put(m.group(), keyword_counts.get(m.group()+1));
                 System.out.println(m.group()+" "+keyword_counts.get(m.group()) );
             }
         }
         else
         {
             if(m.group()!="" || m.group()!=" ")
             {
                 keyword_counts.put(m.group(), 1);
                 System.out.println(m.group()+" "+keyword_counts.get(m.group()) );
             }
         }                  
    }
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  1. Editorial Team
    Editorial Team
    2026-06-02T02:05:45+00:00Added an answer on June 2, 2026 at 2:05 am

    Your test should probably be:

     keyword_counts.containsKey(m.group());
    

    And you should use equals to compare strings instead of == or != but that is not the reason for your issue.

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