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Home/ Questions/Q 8986339
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T21:31:34+00:00 2026-06-15T21:31:34+00:00

I am using a QSpinBox that can be used to input values from 0

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I am using a QSpinBox that can be used to input values from 0 to 33. The default value is zero. If I use the keyboard to enter numbers it keeps the leading zero, which is annoying.

Example: I want to enter 23 via the keyboard

I type “2” – the value of the spinbox changes to “02”

I type “3” – nothing happens – the spinbox is full

How do I prevent this behavior?

thanks,
A

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  1. Editorial Team
    Editorial Team
    2026-06-15T21:31:35+00:00Added an answer on June 15, 2026 at 9:31 pm

    Add a line of code in the valueChanged listener to remove a leading zero.

    if (mySpinBox.value.length() > 1 && mySpinBox.value[0] == '0')
    {
         mySpinBox.value = mySpinBox.value.remove(0, 1);
    }
    
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