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Home/ Questions/Q 8976187
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T19:04:21+00:00 2026-06-15T19:04:21+00:00

I am using AJAX function. I am passing 3 variables to the next page

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I am using AJAX function. I am passing 3 variables to the next page using AJAX. When I add the 4th variable the function doesn’t get called.

Code:
     <script language="javascript" type="text/javascript">
            //Browser Support Code
            function ajaxFunction(){
                var ajaxRequest;  // The variable that makes Ajax possible!

                try{
                    // Opera 8.0+, Firefox, Safari
                    ajaxRequest = new XMLHttpRequest();
                } catch (e){
                    // Internet Explorer Browsers
                    try{
                        ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP");
                    } catch (e) {
                        try{
                            ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP");
                        } catch (e){
                            // Something went wrong
                            alert("Your browser broke!");
                            return false;
                        }
                    }
                }
                // Create a function that will receive data sent from the server
                ajaxRequest.onreadystatechange = function(){
                    if(ajaxRequest.readyState == 4){

                        var ajaxDisplay = document.getElementById('ajaxDiv');
                        ajaxDisplay.innerHTML = ajaxRequest.responseText;
                    }
                }


             var count = document.getElementById('count').value;
             var type = document.getElementById('type').value;
             var sem = document.getElementById('sem').value;
              var rid = document.getElementById('room').value;


          ajaxRequest.open("GET", "add_requi_ajax.php?count=" + count+"&type="+ type+"&sem="+sem+"&rid="+rid, true);

        ajaxRequest.send(null);
    };
</script>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T19:04:23+00:00Added an answer on June 15, 2026 at 7:04 pm

    Your code is syntactically and logically correct, which means that the problem is likely one of your input IDs is wrong (typo? Should room be rid?), or you call the function before the inputs are rendered on the page (use window.onload).

    Verify each of your input IDs. If they all look correct, then comment them out and hard code the values to rule out your inputs as a problem. Watch the error console for any error messages. If an uncaught error is encountered, it can appear that the function isn’t being called.

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