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Home/ Questions/Q 7914087
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T13:59:54+00:00 2026-06-03T13:59:54+00:00

I am using an Ajax request to post a form with Jquery. $.ajax( {

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I am using an Ajax request to post a form with Jquery.

$.ajax( 
        { 
            type: "POST", 
            url: "login.php", 
            data: $("#signin").serialize(),
            dataType: "json",
            cache: false,
            success: function(data, textStatus) {
                if (data.redirect) {
                    window.location.replace(data.redirect);
                }
                else {
                    $('#some').fadeOut(200);
                    $('#some2').fadeIn(200);
                    $("#some3").html(data.form);
                    $("#some").delay(2000).fadeOut(200);
                    $('#some2').delay(2800).fadeIn(300);
                }
            }           
        });

Now the ajax request will take place as soon as you click on a button “Login”. The problem now is that if you press the button more than once the else case will be executed several times which will cause #some, #some2 and #some3 to fade out and in several times. So how could I check whether the request has allready been sent (without having to write something into my db)?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-03T13:59:54+00:00Added an answer on June 3, 2026 at 1:59 pm

    From here:

    You can use .one() method and set it again in ajax callback.

    function doAjax(){
        // Your Ajax call.
        $.ajax({..., complete: function() {
            // Ajax call done, re-enabling the button/link
            $("#buttonId").one('click', doAjax);
        }, ...});
    }
    
    $("#buttonId").one('click', doAjax);
    
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