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Home/ Questions/Q 6826745
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T22:11:03+00:00 2026-05-26T22:11:03+00:00

I am using an Executor with 4 threads. Executor exec = Executors.newFixedThreadPool(this.numOfThreads); Runnable requestHandler

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I am using an Executor with 4 threads.

Executor exec = Executors.newFixedThreadPool(this.numOfThreads);
        Runnable requestHandler = new Runnable() {
            @Override
            public void run() {
                try {
                    getImageForURL(spURL, 0);
                } catch (IOException ex) {
                } catch (Exception ex) {
                }
            }
        };
        exec.execute(requestHandler);

In getImageForURL, I am printing the name of the thread and the output looks like this. The output does not look right, or is this how it is suppose to look?

name=pool-1-thread-1
name=pool-2-thread-1
name=pool-3-thread-1
name=pool-4-thread-1
name=pool-5-thread-1
name=pool-6-thread-1
name=pool-7-thread-1
name=pool-8-thread-1
name=pool-9-thread-1
name=pool-10-thread-1
name=pool-11-thread-1
name=pool-12-thread-1
name=pool-13-thread-1
name=pool-14-thread-1
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  1. Editorial Team
    Editorial Team
    2026-05-26T22:11:04+00:00Added an answer on May 26, 2026 at 10:11 pm

    You are creating a new pool every time (by repeatedly calling newFixedThreadPool). You probably want to create the pool just once (when you start your program), and submit multiple requestHandler to it.

    The output should then look something like:

    name=pool-1-thread-1
    name=pool-1-thread-1
    name=pool-1-thread-2
    name=pool-1-thread-1
    name=pool-1-thread-1
    name=pool-1-thread-2
    

    with the thread number going up to 4 if the pool is fully utilized.

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