Home/ Questions/Q 8524747
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-06-11T07:46:32+00:00

I am using an oracle 11 table with interval partitioning and list subpartitioning like

  • 0

I am using an oracle 11 table with interval partitioning and list subpartitioning like this (simplified):

CREATE TABLE LOG
(
  ID NUMBER(15, 0) NOT NULL PRIMARY KEY
, MSG_TIME DATE NOT NULL
, MSG_NR VARCHAR2(16 BYTE)
) PARTITION BY RANGE (MSG_TIME) INTERVAL (NUMTOYMINTERVAL (1,'MONTH'))
  SUBPARTITION BY LIST (MSG_NR)
    SUBPARTITION TEMPLATE (
     SUBPARTITION login VALUES ('FOO')
   , SUBPARTITION others VALUES (DEFAULT)
   )
   (PARTITION oldvalues VALUES LESS THAN (TO_DATE('01-01-2010','DD-MM-YYYY')));

How do I drop a specific subpartitition for a specific month without knowing the (system generated) name of the subpartition? There is a syntax “alter table … drop subpartition for (subpartition_key_value , …)” but I don’t see a way to specify the month for which I am deleting the subpartition. The partition administration guide does not give any examples, either. 8-}

Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    As it turns out, the “subpartition for” syntax does indeed work, though that seems to be a secret Oracle does not want to tell you about. 🙂

    ALTER TABLE TB_LOG_MESSAGE DROP SUBPARTITION FOR 
      (TO_DATE('01.02.2010','DD.MM.YYYY'), 'FOO')

    This deletes the subpartition that would contain MSG_TIME 2010/02/01 and MSG_NR FOO. (It is not necessary that there is an actual row with this exact MSG_TIME and MSG_NR. It throws an error if there is no such subpartition, though.)

    • 0