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Home/ Questions/Q 3348188
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T01:30:44+00:00 2026-05-18T01:30:44+00:00

I am using an unsigned char to store 8 flags. Each flag represents the

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I am using an unsigned char to store 8 flags. Each flag represents the corner of a cube. So 00000001 will be corner 1 01000100 will be corners 3 and 7 etc. My current solution is to & the result with 1,2,4,8,16,32,64 and 128, check whether the result is not zero and store the corner. That is, if (result & 1) corners.push_back(1);. Any chance I can get rid of that ‘if’ statement? I was hoping I could get rid of it with bitwise operators but I could not think of any.

A little background on why I want to get rid of the if statement. This cube is actually a Voxel which is part of a grid that is at least 512x512x512 in size. That is more than 134 million Voxels. I am performing calculations on each one of the Voxels (well, not exactly, but I won’t go into too much detail as it is irrelevant here) and that is a lot of calculations. And I need to perform these calculations per frame. Any speed boost that is minuscule per function call will help with these amount of calculations. To give you an idea, my algorithm (at some point) needed to determine whether a float was negative, positive or zero (within some error). I had if statements in there and greater/smaller than checks. I replaced that with a fast float to int function and shaved of a quarter of a second. Currently, each frame in a 128x128x128 grid takes a little more than 4 seconds.

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  1. Editorial Team
    Editorial Team
    2026-05-18T01:30:45+00:00Added an answer on May 18, 2026 at 1:30 am

    I would consider a different approach to it entirely: there are only 256 possibilities for different combinations of flags. Precalculate 256 vectors and index into them as needed.

    std::vector<std::vector<int> > corners(256);
    for (int i = 0; i < 256; ++i) {
        std::vector<int>& v = corners[i];
        if (i & 1) v.push_back(1);
        if (i & 2) v.push_back(2);
        if (i & 4) v.push_back(4);
        if (i & 8) v.push_back(8);
        if (i & 16) v.push_back(16);
        if (i & 32) v.push_back(32);
        if (i & 64) v.push_back(64);
        if (i & 128) v.push_back(128);
    }
    
    for (int i = 0; i < NumVoxels(); ++i) {
        unsigned char flags = GetFlags(i);
        const std::vector& v = corners[flags];
    
        ... // do whatever with v
    }
    

    This would avoid all the conditionals and having push_back call new which I suspect would be more expensive anyway.

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