Question

i am using asp.net 2.0 in my project using file upload control , so browse the drive and select the file like path(D:\user doc new 2011\Montana\MT_SUTA_2010-2011.html)
but in my code seeing error is could not find the file path is
(D:\Paymycheck\OnlineTaxUserDocumentation-1\TaxesDocument\MT_SUTA_2010-2011.html) actually it is application path and take the filename only my code is

if (FileUpload.HasFile)
        {
string filepath = Server.MapPath(FileUpload.FileName);
string strHTML = File.ReadAllText(filepath);
                System.Text.ASCIIEncoding encoding = new System.Text.ASCIIEncoding();
                byte[] file1 = encoding.GetBytes(strHTML);
                int len = file1.Length;
                byte[] file = new byte[len]; 

                docs.TaxAuthorityName = ddlTaxAuthority.SelectedItem.Text;
                docs.TaxTypeID = ddlTaxType.SelectedValue;
                docs.TaxTypeDesc = ddlTaxType.SelectedItem.Text;
                docs.EffectiveDate = Convert.ToDateTime(txtEffectiveDate.Text);

                docs.FileName = f1;
                if (ddlTaxAuthority.SelectedValue == "FD")
                {

                    docs.Add(strHTML, file1);
                }
}

error occoured in this line

string strHTML = File.ReadAllText(filepath);

i can try like this also

string FolderToSearch = System.IO.Directory.GetParent(FileUpload.PostedFile.FileName).ToString();
string f = Path.GetDirectoryName(FileUpload.PostedFile.FileName);
string f1 = FileUpload.FileName;
                 string filepath = System.IO.Path.GetFullPath(FileUpload.PostedFile.FileName);
 string strFilePath = FileUpload.PostedFile.FileName;
string file1234 = System.IO.Path.GetFullPath(FileUpload.PostedFile.FileName);
string filepath = FileUpload.PostedFile.FileName;

so how to get the total path drive to file
pls help me any one

thank u
hemanth

Answer 1

Because your are using Server.MapPath, which according to MSDN “maps the specified relative or virtual path to the corresponding physical directory on the server.” You have to first call FileUpload.SaveAs method to save file on server then try to read it’s content.