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Home/ Questions/Q 783755
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T20:36:00+00:00 2026-05-14T20:36:00+00:00

I am using ASP.NET MVC with jQuery. I have the following MVC Action that

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I am using ASP.NET MVC with jQuery. I have the following MVC Action that returns a partial page on Success. On Application Error, I am not sure what to send it for correctly handling it at the client side:

public ActionResult LoadFilterSet(int filterSetId)
{
    try
    {
        BreadCrumbManager bcManager = this.ResetBreadCrumbManager(this.BreadCrumbManagerID);
        GeneralHelper.LoadBreadCrumbManager(bcManager, filterSetId);

        ViewData["BreadCrumbManager"] = bcManager;
        return View("LoadFilterSet");
    }
    catch (Exception ex)
    {
        return Content("");
    }
}

Following is my jQuery ajax call. Notice that I am checking for the data length to make sure there are no errors. Please suggest me a better way of doing this.

$.ajax({
    type: "GET",
    dataType: "html",
    async: true,
    data: ({ filterSetId: selectedId }),
    url: link,
    contentType: "text/html; charset=utf-8",
    success: function(data, textStatus) {
        if (data.length > 0) {
            // Clear the local filters first.
            clearLocalFilters();
            $('td.selected-filters table.filters-display').append(data);
        }
    }
});
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  1. Editorial Team
    Editorial Team
    2026-05-14T20:36:00+00:00Added an answer on May 14, 2026 at 8:36 pm

    I would add an error function in your setup of the ajax call. Let the server determine the error message to display and pass it the ajax error handler and let it display it.

    success: function(data, textStatus) {     
        // Clear the local filters first.     
        clearLocalFilters();     
        $('td.selected-filters table.filters-display').append(data);         
    },
    error: function (data) { 
        alert(data.responseText); // use any display logic here
    }
    

    In your controller’s action, if an error is found

    Response.StatusCode = (int)HttpStatusCode.BadRequest; 
    return Content(errorMessage, MediaTypeNames.Text.Plain);
    
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