Question

I am using AsyncTask Class to handle images that are coming from the server to display it in the ImageView
I have one Next button in my code to call the next image using following code:

private class LoadImage extends AsyncTask<Void, Void, Void> {

    @Override
    protected void onPostExecute(Void result) {

        if (imgque != null) {
            imgSelectedQue.setImageDrawable(imgque);
            if (getActivity() != null) {
                adjustResourceEnvelope();
            }
        }

    }

    @Override
    protected void onPreExecute() {
        imgque = null;
        imgSelectedQue.setImageDrawable(null);
        imgSelectedQue.requestLayout();
    }

    @SuppressWarnings("deprecation")
    @Override
    protected Void doInBackground(Void... params) {
        InputStream is;
        try {
            is = (InputStream) new URL(Constants.PLAYER_SERVICE_BASE_URL + "/playerservice"
                    + imageurl).getContent();
            imgque = Drawable.createFromStream(is, null);
        } catch (MalformedURLException e) {
            e.printStackTrace();
        } catch (IOException e) {
            imgque = null;
            e.printStackTrace();
        }

        return null;

    }
}

Now the issue is that if I click the next button REPEATEDLY then it call the AsyncTask that many times and ImageView displaying all the images like “Slide-Show” because all the url images are in queue.
Is there any way to display only last AsyncTask call image?

Answer 1

I Found the Solution for this.
If anyone facing the same issue.
I Added new lines

if (loadimage != null)
 {
   loadimage.cancel(true);
   loadimage = null;
}

loadimage.cancel(true) will stop the AsyncTask if it is already Running

then execute the AsycTask()

loadimage = new LoadImage();
loadimage.execute();

In this way i am able to call only last AsyncTask that what I required.