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Home/ Questions/Q 8493835
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T23:07:50+00:00 2026-06-10T23:07:50+00:00

I am using Bash script to read line by line from a text file,

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I am using Bash script to read line by line from a text file, which has special characters in it (regular expression). When I use echo "${SOME_VAR}" it does not display the text as is.

I am familiar with Prevent * to be expanded in the bash script.

How can I display and use the text as is?

UPDATE
The text (TSV) file holds tuples similar to (the last entry is a psql query)

bathroom    bathroom    select name from photos where name ~* '\mbathroom((s)?|(''s)?)\M';

I am reading the CSV as follows:

tail -n+2 text.file | while IFS=$'\t' read x y z
do
    echo "${z}"
done

which gives the output

select name from photos where name ~* 'mbathroom((s)?|(''s)?)M');

note that the ‘\’ is missing

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-10T23:07:52+00:00Added an answer on June 10, 2026 at 11:07 pm

    Try using the -r flag with read:

    tail -n+2 text.file | while IFS=$'\t' read -r x y z
    do
        echo "${z}"
    done
    

    From the read man page:

    -r Do not treat a backslash character in any special way. Consider each backslash to be part of the input line.

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