Question

I am using below to get the time remaining for playing games on iPhone.

int minutes_games_iPhone5 = 600;//minutes of 10 hour (static)

    int games_iPhone5=(minutes_games_iPhone5*batteryinfo)/100;
    int hour_game_iPhone5 = games_iPhone5/60;
    int min_game_iPhone5 = games_iPhone5%60;

log :hour:min = 8:30

Which works well, i guess.Now i need to figure out how can i show the same output in percentage,like 50%.

So 8:30 should also represent the value in percentage.How can i do that?

Thanks

Answer 1

8 hour 30 mintues equals to 8*60 + 30= 480+30=510min

Total time is 600min.

Therefore % is 510/600*100.

Convert this thing to code you will get the percent.

But use double/float otherwise you may end up with 0*100 in (510/600=0). Make it 510.0/600.