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Home/ Questions/Q 8843123
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T11:08:24+00:00 2026-06-14T11:08:24+00:00

I am using boost::split(strs, r_strCommandLine, boost::is_any_of(\t )); to spit a string into tokens for

  • 0

I am using

boost::split(strs, r_strCommandLine, boost::is_any_of("\t "));

to spit a string into tokens for parsing a simple script. So far, so good. However, for the following string

command_name first_argument "Second argument which is a quoted string." 

i would like my tokens to be

strs[0] = command_name
strs[1] = first_argument
strs[2] = "Second argument which is a quoted string." 

Of course, I could search for quote characters at beginning and ending of tokens and merging using ” ” delimiters the tokens between the the occurrence of a token beginning with a quote and a token ending with a quote to recreate the quoted string but I am wondering if there is a more efficient/elegant way of doing this. Any ideas?

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  1. Editorial Team
    Editorial Team
    2026-06-14T11:08:26+00:00Added an answer on June 14, 2026 at 11:08 am

    Example using boost::tokenizer:

    #include <string>
    #include <iostream>
    using std::cout;
    using std::string;
    
    #include <boost/tokenizer.hpp>
    using boost::tokenizer;
    using boost::escaped_list_separator;
    
    typedef tokenizer<escaped_list_separator<char> > so_tokenizer;
    
    int main()
    {
        string s("command_name first_argument "
                 "\"Second argument which is a quoted string.\"");
    
        so_tokenizer tok(s, escaped_list_separator<char>('\\', ' ', '\"'));
        for(so_tokenizer::iterator beg=tok.begin(); beg!=tok.end(); ++beg)
        {
            cout << *beg << "\n";
        }
    
        return 0;
    }
    

    Output:

    command_name
    first_argument
    Second argument which is a quoted string.
    

    See demo at https://ideone.com/gwCpug .

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