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Home/ Questions/Q 3225786
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T16:22:47+00:00 2026-05-17T16:22:47+00:00

I am using C++. C++0x using Visual Studio 2010 to be correct. Suppose I

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I am using C++. C++0x using Visual Studio 2010 to be correct.

Suppose I have a class Z. To make it safer in my application to work with pointers to this class, I can consistently use smart pointers (shared pointer, weak pointer).

Now this class Z inherits from a class X. Some parts of my application will work with pointers to class X, others will work with pointers to class Z.

  • Can I still use smart pointers?
  • Do shared pointers still work if I have some that refer to X and others that refer to Z? Is it guaranteed that the destruction of the last shared pointer to the instance (regardless of whether it is std::shared_ptr<X> or std::shared_ptr<Z>) deletes the instance? Am I sure that if I delete std::shared_ptr<X>, that the instance is kept as long as there is another std::shared_ptr<Y>?

Now suppose that I use multiple inheritance, where Z inherits from classes X and Y.
Some parts of my application will work with std::shared_ptr<X>, others with std::shared_ptr<Y> and others with std::shared_ptr<Z>.

  • Can I still use shared pointers this way?
  • Is it still guaranteed that only the last smart pointer (regardless of whether it points to X, Y or Z) deletes the instance?

By the way, how can I safely cast one smart pointer to another, e.g. cast std::shared_ptr<Z> to std::shared_ptr<X>? Does this work? Is this allowed?

Notice that I explicitly refer to non-intrusive pointers (as the new std::shared_ptr and std::weak_ptr in C++0x). When using intrusive pointers (like in Boost), it probably works since the instance itself is responsible for keeping the counter.

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  1. Editorial Team
    Editorial Team
    2026-05-17T16:22:48+00:00Added an answer on May 17, 2026 at 4:22 pm

    Yes this is supported by the standard, §20.9.11.2.10 [util.smartptr.shared.cast].

    The utils you need are:

    • std::static_pointer_cast<>()
    • std::dynamic_pointer_cast<>()

    They have the same semantics as their C++03 counter parts static_cast<>() and dynamic_cast<>(). The one difference being that they only work on std::shared_ptrs. And just to verbose, they do what you expect and correctly share the reference count between the original and newly cast shared_ptrs.

    struct X { virtual ~X(){} };
    struct Y : public X {};
    struct Z : public X {};
    
    int main()
    {
       {
          //C++03
          X* x = new Z;
          Z* z = dynamic_cast<Z*>(x);
          assert(z);
          x = new Y;
          z = dynamic_cast<Z*>(x);
          assert(!z);
          z = static_cast<Z*>(x);
          assert(z); //EVIL!!!
       }
    
       {
          //C++0x
          std::shared_ptr<X> x{new Z};
          std::shared_ptr<Z> z{std::dynamic_pointer_cast<Z>(x)};
          assert(z);
          x = std::make_shared<Y>();
          z = std::dynamic_pointer_cast<Z>(x);
          assert(!z);
          z = std::static_pointer_cast<Z>(x);
          assert(z); //EVIL!!!
    
          // reference counts work as expected.
          std::shared_ptr<Y> y{std::static_pointer_cast<Y>(x)};
          assert(y);
    
          std::weak_ptr<Y> w{y};
          assert(w.expired());
    
          y.reset();
          assert(w.expired());
    
          x.reset();
          assert(!w.expired());      
       }
       {
          //s'more nice shared_ptr features
          auto z = std::make_shared<X>();
          std::shared_ptr<X> x{z};
          assert( z == x );
          x = z; //assignment also works.
       }
    }
    
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