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Home/ Questions/Q 988445
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T05:38:16+00:00 2026-05-16T05:38:16+00:00

I am using codeigniter framework and in view i am using jquery. Now, I

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I am using codeigniter framework and in view i am using jquery. Now, I have one select box which contains values from database. I tested the values of it using jquery change event and alert box. Its giving exact value in alert box on change, but when i am using post method or get or even $.ajax(), its not giving any output. In fact i checked with console.log(), its not going inside that too. I just need to post some values and get some info from database to show in the div just below that select box.
Here’s the code for jquery:

$(document).ready(function(){
   $('#org_name').change(function(){
       $.post('index.php/contact/getorg',{'query':$('#org_name').val()},function(data){
         console.log("inside post"); 
         $('#showorg').html(data);
         console.log(org_name);
       });//close post function
   }); //close org_name event function
});
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T05:38:17+00:00Added an answer on May 16, 2026 at 5:38 am

    I am always using the following style…

    ajax({
       type: "POST",
       url: 'index.php/contact/getorg',
       data: JSON.stringify({'query':$('#org_name').val()}),
       dataType: "json",
       contentType: "application/json; charset=utf-8",
       success: function (data) {
          $('#showorg').html(JSON.parse(data.d));
       },
       error: showError
    };
    
    function showError(responseText, statusText, xhr, $form) {
                debugger;         }
    

    EDIT:

    And also the line console.log(org_name); seems not correct. Where is the member org_name comming from?

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