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Home/ Questions/Q 6706359
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T07:30:41+00:00 2026-05-26T07:30:41+00:00

I am using DevC++ 4.9, running on WinXP SP3 (32bit), here is the code:

  • 0

I am using DevC++ 4.9, running on WinXP SP3 (32bit), here is the code:

#include <stdio.h>
#include <stdlib.h>

main(int argc, char *argv[])
{
    double value;

    int i;

    printf("Enter double: ");
    scanf("%lf", &value);
    i = value*100;
    printf("double: %lf\n", value);
    printf("int: %d\n", i);

  system("PAUSE");  
}

I have entered different values and here are the results:

Test 1:

enter image description here

Test 2:

enter image description here

Test 3:

enter image description here

Why Test 1 and Test 2 displayed different results??

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  1. Editorial Team
    Editorial Team
    2026-05-26T07:30:42+00:00Added an answer on May 26, 2026 at 7:30 am

    This is due to floating-point round-off:

    What Every Computer Scientist Should Know About Floating-Point Arithmetic:
    http://download.oracle.com/docs/cd/E19957-01/806-3568/ncg_goldberg.html

    3.07 cannot be exactly represented in binary. In your case, it’s being rounded to slightly less than 3.07, therefore 100 * 3.07 is evaluating to 306.9999999..., which is truncated to 306.

    Same applies to 3.05. But 3.06, is rounded slightly up. So 100 * 3.06 correctly shows up as 306.

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