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Home/ Questions/Q 915057
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T17:49:25+00:00 2026-05-15T17:49:25+00:00

I am using django forms to add a new objects to the db. The

  • 0

I am using django forms to add a new objects to the db. The code I currently have is:

if request.method == 'POST':
    form = MyForm(data=request.POST)

    if form.is_valid():
        obj = form.save()
 else:
    form = MyForm()

return render_to_response('reflections/add_reflection.html', {'form':form},context_instance=RequestContext(request))

The code above currently adds a new object each time the form is submitted. What I want to happen is that the object is edited the next time the save button is pressed rather than adding a new record.

How would I do this?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T17:49:26+00:00Added an answer on May 15, 2026 at 5:49 pm

    Use

     instance_id = None
     if request.method == 'POST':
        try:
            instance = MyType.objects.get(id=request.POST.get('instance_id'))
        except MyType.DoesNotExist:
            instance = None
        form = MyForm(data=request.POST, instance=instance)
    
        if form.is_valid():
            obj = form.save()
            instance_id = obj.id
     else:
        form = MyForm(instance=None)
    
    return render_to_response('reflections/add_reflection.html', {'form':form, 'instance_id': instance_id or ''},context_instance=RequestContext(request))
    

    Once the object is saved, pass it’s id in context to page
    and add it to a hidden input field inside the form as name=’instance_id’.

    Happy Coding.

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