Question

I am using find to find names of databases that return some rows for a query.

$ find . -name 'sqlite.db' -exec sqlite3 "{}" 'SELECT * FROM table WHERE column1="value"' \; 

value|a|b|c|d

But I want the name of the database, so I tried -print which showed all the names

$ find . -name 'sqlite.db' -print -exec sqlite3 "{}" 'SELECT * FROM table WHERE column1="value"' \; 

/dir1/a/sqlite.db
value|a|b|c|d
/dir2/a/sqlite.db
/dir2/b/sqlite.db
/dir3/a/sqlite.db

Is there a way I can get only the files where the exit status of the command run is success.

Answer 1

You just need to -print after the -exec. It is a short circuiting boolean and, and by putting -print before -exec, the print happens before the exec does.

find . -name sqlite.db -exec ... \; -print