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Home/ Questions/Q 8161897
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T18:35:45+00:00 2026-06-06T18:35:45+00:00

I am using flask , and trying to do something very simple using the

  • 0

I am using flask, and trying to do something very simple using the quickstart tutorial, just running on my machine (local server). I produce a simple upload form which successfully uploads an image file. I then want to pass this image as a variable to a template.html for display within a page. The template.html file displays fine, but the image is always a broken link image symbol. I’ve tried a number of different paths, but I have a feeling I am doing things a bit wrong.

import os
from flask import Flask, request, redirect, url_for, send_from_directory, 
                  render_template

UPLOAD_FOLDER = '/home/me/Desktop/projects/flask/uploads'
ALLOWED_EXTENSIONS = set(['txt', 'pdf', 'png', 'jpg', 'jpeg', 'gif'])

app = Flask(__name__)
app.config['UPLOAD_FOLDER'] = UPLOAD_FOLDER

def allowed_file(filename):
    return '.' in filename and \
           filename.rsplit('.', 1)[1] in ALLOWED_EXTENSIONS

@app.route('/', methods=['GET', 'POST'])
def upload_file():
    if request.method == 'POST':
        file = request.files['file']
        if file and allowed_file(file.filename):
            filename = secure_filename(file.filename)
            file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename))
            return redirect(url_for('uploaded_file', filename=filename))
    return '''
    <!doctype html>
    <title>Upload new File</title>
    <h1>Upload new File</h1>
    <form action="" method=post enctype=multipart/form-data>
      <p><input type=file name=file>
         <input type=submit value=Upload>
    </form>
    '''

@app.route('/uploads/<filename>')
def uploaded_file(filename):
    filename = 'http://127.0.0.1:5000/uploads/' + filename
    return render_template('template.html', filename = filename)

if __name__ == '__main__':
    app.run()

This is template.html:

<!doctype html>
<title>Hello from Flask</title>
{% if filename %}
  <h1>some text<img src="{{filename}}"> more text!</h1>
{% else %}
  <h1>no image for whatever reason</h1>
{% endif %}

How can I pass the uploaded image file to template.html so it will display correctly?

Thanks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T18:35:47+00:00Added an answer on June 6, 2026 at 6:35 pm

    What’s happening now is that /uploads/foo.jpg returns the HTML inside template.html. There you try to use /uploads/foo.jpg as the source of the img tag. Nowhere you serve the actual image out.

    Let’s modify it like this: /show/foo.jpg returns the HTML page and and /uploads/foo.jpg returns the image. Replace the latter route with these two and you should be good to go:

    @app.route('/show/<filename>')
    def uploaded_file(filename):
        filename = 'http://127.0.0.1:5000/uploads/' + filename
        return render_template('template.html', filename=filename)
    
    @app.route('/uploads/<filename>')
    def send_file(filename):
        return send_from_directory(UPLOAD_FOLDER, filename)
    
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