Question

I am using following class to show a grid like appearance with pagination on my home page. The class is very good and is working fine.

When the grid shows records, I just want to make the second column values as a hyperlink. I tried adding a href … in the class where $c is updating, but it is not working. Can anyone help me out.

This class also uses “style.css” file that is also available from the link below. Are any changes needed there?

http://www.webmastergate.com/php/paginate-query-results.html

Answer 1

In the function getRows(), near the very last lines of the function where the $c variable is set. You have to somehow test whether this is the column you want to add the link. Suggest that you set up another associative array which store a key and a callback function

   $r = '';
    while ($row = mysql_fetch_assoc($result)) {
        $c = '';

        foreach($row as $key=>$field) {
                //manipulate data here
            $c .= $this->fmtField($key, $field);
        }
        $r .= sprintf($this->rowfmt, $cr ? $classodd : $classeven, $c);
        $cr = 1 - $cr;
    }

Another datagrid I will recommend is http://www.eyesis.ca/projects/datagrid.html – it partly removes the need to add in link as you can add custom actions to each row.