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Home/ Questions/Q 8175061
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T22:37:55+00:00 2026-06-06T22:37:55+00:00

I am using following code to show a spinning wheel: $(#loading) .hide() .ajaxStart(function(){ $(this).show();

  • 0

I am using following code to show a spinning wheel:

$("#loading")
.hide()
.ajaxStart(function(){

    $(this).show();
    setTimeout("3000");
})
.ajaxStop(function(){

    $(this).hide("slow");
})
;   

and:

<div id="loading">
            <img src="loading.gif" alt="Loading" />
</div>  

Problem:
“setTimeout() is not working. And how can I display the image at the centre of webpage?”

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T22:37:56+00:00Added an answer on June 6, 2026 at 10:37 pm

    I dont understand why you’re using the timer, you can simply turn it on at start of ajax request, and then on success or error turn it off, like:

    $('#loading').show();
    
    $.post(url, request)
    
        .success(function(data) {
            $('#loading').hide();
            // Do what you want with data
        })
    
        .error(function(data) {
            $('#loading').hide();
            // Show error message
        });
    

    To have your loading image in the middle of the page, make sure that it’s container is within a 100% height parent, and if it is nested, make sure none of its parents are position:relative.

    #loading {
        position:relative;
        width:100%;
        height:100%;
    }
    
    #loading img {
        margin-top: -12px; // Half images height;
        margin-left: -12px; // Half images width;
        position:absolute;
        top:50%;
        left:50%;
    }
    
    OR
    
    #loading {
        width:100%;
        height:100%;
    }
    
    #loading img {
        width:24px // Images width
        height:auto; // If Image size changes don't mess with proportions
        margin:0 auto;
        margin-top:48%;
    }
    
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