Question

I am using Fullcalendar for jQuery and for some reason the calendar is appearing twice on the page. This is not a question about having two instances of fullcalendar on the same page.

Rather, at the bottom of the first calendar, there is a second identical calendar.

I confirmed that there is only one #calendar div in my page, so the error has something to do with my .js that calls fullcalendar.js, I believe.

Any help much appreciated.

JS Code:

jQuery('#calendar').fullCalendar({


        year: jQuery.today.getFullYear(),
        month: jQuery.today.getMonth(),
        date: jQuery.today.getDate(),
        theme: true,
        contentHeight: 1000,
        header: {
            left: 'prev,next today',
            center: 'title',
            right: 'month,agendaWeek,agendaDay'
        },
        defaultView: 'agendaDay',
        dayClick: function(date, allDay, jsEvent, view) {
                           // a lot of custom code
                    }
            });

HTML:

<table><tr><td valign="top" width="700px"><div id="calendar"></div></td></tr></table>

Other call of fullcalendar in javascript (this puts a datepicker in div to left of #calendar div on same page):

jQuery('#datepicker_for_calendar').datepicker({
          defaultDate: jQuery.today,
          minDate: jQuery.startDate,
          maxDate: jQuery.endDate,
          inline: true,
          showButtonPanel: true,
          onSelect: function(dateText, inst) {
              var d = new Date(dateText);
              jQuery('#calendar').fullCalendar('gotoDate', d);
              selectedDate = d;
          }
      });

Answer 1

Ok, after a long week of bug testing everything, I found this jQuery plugin:

once()

http://plugins.jquery.com/project/once

Once applied to the #calendar div before .fullcalendar, problem solved, only one calendar rendered.

Working code:

jQuery('#calendar').once('calendar').fullCalendar({

…
})