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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T08:06:27+00:00 2026-05-20T08:06:27+00:00

I am using Hibernate and JPA. If I have two simple entities: @Entity @Table(name

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I am using Hibernate and JPA. If I have two simple entities:

@Entity
@Table(name = "container")
public class Container {
  @Id
  @Column(name="guid")
  private String guid;
}

@Entity
@Table(name="item")
public class Item {
  @Id
  @Column(name="guid")
  private String guid;

  @Column(name="container_guid")
  private String containerGuid;
}

and I want to insure that inserting an Item fails if the referenced Container does not exist. I would prefer not to have a Container object populated inside the item object (ManyToOne), how would I do this if it is possible to do?

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  1. Editorial Team
    Editorial Team
    2026-05-20T08:06:28+00:00Added an answer on May 20, 2026 at 8:06 am

    You can declare arbitrary constraint using columnDefinition attribute:

    @Column(name="container_guid", 
         columnDefinition = "VARCHAR(255) REFERENCES container(guid)")
    private String containerGuid;
    

    Note, however, that Hibernate doesn’t know anything about this constraint, so that, for example, it may not perform inserts in proper order with respect of it and so on.

    Therefore it would be better to create a @ManyToOne relationship. If you are afraid of extra SQL query for Container needed to set this property, you can use Session.load()/EntityManager.getReference() to get a proxy without issuing actulal query.

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