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Home/ Questions/Q 6981717
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T18:11:37+00:00 2026-05-27T18:11:37+00:00

I am using Hibernate’s lazy loading, and am getting sessionFactory missing exception, even after

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I am using Hibernate’s lazy loading, and am getting sessionFactory missing exception, even after I have defined a filter in web.xml to use OpenSessionInViewFilter

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<!-- The definition of the Root Spring Container shared by all Servlets and Filters -->
<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>/WEB-INF/spring/root-context.xml</param-value>
</context-param>

<!-- Creates the Spring Container shared by all Servlets and Filters -->
<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

<!-- Processes application requests -->
<servlet>
    <servlet-name>appServlet</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
    <servlet-name>appServlet</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>
<filter>
    <filter-name>hibernateFilter</filter-name>
    <filter-class>
       org.springframework.orm.hibernate3.support.OpenSessionInViewFilter
    </filter-class>
</filter>
<filter-mapping>
    <filter-name>hibernateFilter</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping> 
</web-app>

My servlet-context.xml has following session and transaction manager definitions:

<beans:bean id="sessionFactory" class="org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean">
    <beans:property name="dataSource" ref="dataSource"/>
    <beans:property name="hibernateProperties">
        <beans:props>
            <beans:prop key="hibernate.dialect">${connection.dialect}</beans:prop>
            <beans:prop key="hibernate.show_sql">true</beans:prop>
       </beans:props>
    </beans:property>
    <beans:property name="annotatedClasses">
        <beans:list>
            <beans:value>example.EntityA</beans:value>
            <beans:value>example.EntityB</beans:value>
        </beans:list>
    </beans:property>
</beans:bean>

<beans:bean id="transactionManager" class="org.springframework.orm.hibernate3.HibernateTransactionManager">
    <beans:property name="sessionFactory" ref="sessionFactory"/>
</beans:bean>
<tx:annotation-driven transaction-manager="transactionManager" />

I still get the following exception:

org.springframework.beans.factory.NoSuchBeanDefinitionException: No bean named 'sessionFactory' is defined

I have tried defining a sessionFactoryBeanName attribute but results don’t change. What am I doing wrong?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T18:11:38+00:00Added an answer on May 27, 2026 at 6:11 pm

    You need to declare sessionFactory in the root web application context (i. e. /WEB-INF/spring/root-context.xml) to make it available to OpenSessionInViewFilter.

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