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Home/ Questions/Q 7826401
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T09:23:44+00:00 2026-06-02T09:23:44+00:00

I am using imagerotate() function to turn the image below to a 30 degree

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I am using imagerotate() function to turn the image below to a 30 degree angle.

http://postimage.org/image/b7w6dacel/

The problem is that whenever I rotate the image and save it to a new path, in the new path the image is rotated but it has a black color surrounding it, like below.

http://postimage.org/image/n3n1vtr9p/8501961e/

The original image is 450 * 340 and after rotation, the image becomes 560 * 520. Does anyone know what I am doing wrong. Take a look at my source code below. Thanks.

$filename =  "static\\". $sessionid . "-1.jpg";
$file= $sessionid . "-1.jpg";
$ir = imagecreatefromjpeg($filename);
$degrees = 30;
$flip=imagerotate($ir, $degrees, 0);
$rotated=imagejpeg($flip, 'c:\\xampp\\htdocs\\'. $file);
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  1. Editorial Team
    Editorial Team
    2026-06-02T09:23:48+00:00Added an answer on June 2, 2026 at 9:23 am

    Depending on how much you rotate it, the new image will be larger than the original. You will either have to scale or crop the new image. This code will scale $oldImage to $newWidth and $newHeigth.

    $newImage = imagecreatetruecolor($newWidth, $newHeight);
    imagecopyresampled($newImage, $oldImage, 0, 0, 0, 0, $newWidth, $newHeight, imagesx($oldImage), imagesy($oldImage));
    

    Hope this helps.

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