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Home/ Questions/Q 9107647
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T02:37:21+00:00 2026-06-17T02:37:21+00:00

I am using iOS 6’s UIActivityViewController. I would like to share an image that

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I am using iOS 6’s UIActivityViewController.
I would like to share an image that is not available locally on my iPhone, but that it is available on a remote URL.

NSString *textToShare = _eventoTitle;
UIImage *imageToShare = [UIImage imageNamed:_iconUrl];
NSURL *url = [NSURL URLWithString:_permalink];
NSArray *activityItems = [[NSArray alloc]  initWithObjects:textToShare, imageToShare, url, nil];

Unfortunately, this is not working. What am I doing wrong?

I have also tried to use the AFNetworking library:

UIImage *imageToShare = [UIImage alloc];
[*imageToShare setImageWithURL:[NSURL URLWithString:_iconUrl]];

This is not working too.

_iconUrl is something like http://www.mysite.com/picture.png

Thank you, Francesco

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  1. Editorial Team
    Editorial Team
    2026-06-17T02:37:22+00:00Added an answer on June 17, 2026 at 2:37 am

    Try with:

    UIImage *imageToShare = [UIImage imageWithData:[NSData dataWithContentsOfURL:[NSURL URLWithString:[NSString stringWithFormat:@"%@", _iconUrl]]]];
    

    Matteo

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