Question

I am Using Joomla 2.5. I am using MYSQL database.
I have a table job_field with the following columns:

cat_id  |  location_id
-----------------------
 1,4    |   66,70

I need to compare it with another table job_value

cat_id  |  location_id | name
--------------------------------
 1      |   70         | Atul
 4      |   70,80      | Amit
 4      |   80,66      | Amol
 1      |   66         | Pritam    
 3      |   70         | Rahul
 2      |   66,90      | Ajit
 1      |   74         | Raju
 4      |   65,22      | Manoj

I want output to compare cat_id and location_id columns from first table job_details with second table job_value columns cat_id and location_id.

And it will check each value from 1st table (job_details) that is location_id column value (66, 70) separately with 2nd table (job_value) location_id column. I will get output array as

  Array (
    1 70     Atul
    4 70,80  Amit
    4 80,66  Amol
    1 66     Pritam
 )

Answer 1

Try this ::

SELECT 
* 
FROM table1
JOIN table2  ON FIND_IN_SET(table1.location_id, table2.location_id) > 0

You can also refer
Comma separated values in MySQL "IN" clause