Question

I am using jQuery Ajax with PHP. When I use post with jQuery Ajax, then it’s send request to PHP (server). In my PHP code, I want to return status success or error. In case it error, send error code and error message, else, it success return success code and message.

How can I do that in jQuery Ajax with PHP?

Edit:

$.post(url, { id: id },
function(data) {
    // success code do here.
});

Answer 1

Just return array with json encode…

header('Content-Type: application/json');
$array = array("status"=>"success");
echo json_encode($array);
exit();

The exit is to prevent any further echo’s .

At your ajax ..

$.post(url, { id: id },
function(data) {
    alert(data.status);
}, 'json');

the data.status equals to your php array key status ..

to just catch at Ajax error … You can set simple..

header('Content-Type: application/json');
echo "string whithout json_encode";
exit();

In this case change your ajax to …

$.post(url, { id: id },function(data) {}, 'json')
.success(function(data) { alert("success"); })
.error(function(data) { alert("error"); });