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Home/ Questions/Q 9279307
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T17:36:02+00:00 2026-06-18T17:36:02+00:00

I am using jQuery to check if an element is odd or even :

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I am using jQuery to check if an element is odd or even:

 $("#map183").parent().is(':even');

This will return true or false depending on where the element is.

However this will always return false:

   function whereAreWe(myself,range){
        var parent = myself.parent();
        var position = parent.is(':even');
        alert(position);
        //outputs false
   }

   $('.hasSVG').on('click', function(){
        whereAreWe($(this),2);
   });

I have the working example here: JSFiddle

In the example you will see that i am trying to see if the parent(.line) of said element is either odd or even.

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  1. Editorial Team
    Editorial Team
    2026-06-18T17:36:04+00:00Added an answer on June 18, 2026 at 5:36 pm

    This is because the :even selector is only useful within a list
    but parent refers to exactly one object.
    Therefore, :even with a list of 1 does not make sense.

    However, you have IDs that indicate the line-number

    var position = parent.attr("id").substr(4) % 2 == 0;
    console.log(position);
    

    extracting the id and deleting the “line”-string from “lineX” gives you the line-number X.
    A check with MOD 2 (or alternatively a bitwise AND with 1:)

    var position = ((parent.attr("id").substr(4) & 1) == 1);
    

    will do the trick.

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