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Home/ Questions/Q 7248653
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T22:10:04+00:00 2026-05-28T22:10:04+00:00

I am using log4j to log my exceptions. I want to log whatever I

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I am using log4j to log my exceptions. I want to log whatever I get in e.printStackTrace();
My code looks like this:

try {

} catch(Exception e) {
    log.error("Exception is:::" + e);
}

But the content I get logged looks like this:

2012-02-02 12:47:03,227 ERROR [com.api.bg.sample] - Exception in unTech:::[Ljava.lang.StackTraceElement;@6ed322
2012-02-02 12:47:03,309 ERROR [com.api.bg.sample] - Exception is :::java.lang.IndexOutOfBoundsException: Index: 0, Size: 0

But the content I expect is:

java.io.IOException: Not in GZIP format
at java.util.zip.GZIPInputStream.readHeader(Unknown Source)
at java.util.zip.GZIPInputStream.<init>(Unknown Source)
at java.util.zip.GZIPInputStream.<init>(Unknown Source)
at com.api.bg.sample.unGZIP(sample.java:191)
at com.api.bg.sample.main(sample.java:69)

I tried e.getMessage(), e.getStackTrace(); however I don’t get the full stacktrace. Any suggestions?

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  1. Editorial Team
    Editorial Team
    2026-05-28T22:10:04+00:00Added an answer on May 28, 2026 at 10:10 pm

    You have to use the two argument form

    log.error("my logging message", exception)
    

    See http://www.devdaily.com/blog/post/java/how-print-exception-stack-trace-using-log4j-commons for more details.

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