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Home/ Questions/Q 6704399
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T07:17:03+00:00 2026-05-26T07:17:03+00:00

I am using LuaInterface with C#, and have got everything set up correctly. What

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I am using LuaInterface with C#, and have got everything set up correctly.

What I want to be able to do is that when the script is started using lua.DoFile(), that the script has access to a Player object that I can send…

Current Code:

public static void RunQuest(string LuaScriptPath, QPlayer Player)
{
    QMain.lua.DoFile(LuaScriptPath);
}

But as you can see the script will not have access to the Player object.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T07:17:04+00:00Added an answer on May 26, 2026 at 7:17 am

    I see two options. The first one is to make your player a global variable for Lua:

    QMain.lua['player'] = Player
    

    Then you’ll be able to access player in your script

    The second option is to have the script define a function accepting player as parameter. So if your current script contains ...code... now it will contain:

    function RunQuest(player)
        ...code...
    end
    

    and your C# code will look something like this:

    public static void RunQuest(string LuaScriptPath, QPlayer Player)
    {
        QMain.lua.DoFile(LuaScriptPath); // this will not actually run anything, just define a function
        QMain.lua.GetFunction('RunQuest').Call(player);        
    }
    
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