Question

I am using mysqli to query a database table to obtain the value for a dropdownlist. However, I also want to retrieve the corresponding description and load that into the option text. My query is as follows:

<?php 
$query=('SELECT restaurantid,location from restaurant');
$result = mysqli_query($mysqli,$query);
echo '<select name="ddlStore">';
while($row=$mysqli->fetch_array($result))
{
    echo '<option value="' . htmlspecialchars($row['restaurantid']) . '">';
    '</option>';
}
echo '</select>';
?>

How do I revise the above so that the location field is populating in the dropdownlist’s option text?

Updated code:

<?php 
$query=('SELECT restaurantid,location from restaurant');
$result = mysqli_query($mysqli,$query);
echo '<select name="ddlStore">';
while($row=$mysqli->fetch_array($result))
{
    echo '<option value="' . htmlspecialchars($row['restaurantid']) . '">' .
     htmlspecialchars($row['location']) . 
    '</option>';
}
echo '</select>';
?>

The above still does not display the locations as dropdownlist option text values.

Update #2:
When viewing the page, the dropdownlist doesn’t show the values from the database table. Using IE Developer Tools, I see a script error in the while statement:

Call to undefined method mysqli::fetch_array()

Is there a more optimal way to structure the mysqli_fetch_array statement?

Answer 1

Change to…

echo '<option value="' . htmlspecialchars($row['restaurantid']) . '">' . htmlspecialchars($row['location']) . '</option>';