Question

I am using Oracle’s to_char() function to convert a date to a week number (1-53):

select  pat_id, 
    pat_enc_csn_id, 
    contact_date, 
    to_char(contact_date,'ww') week,
    ...

the ‘ww’ switch gives me these values for dates in January of this year:

Date        Week
1-Jan-10    1
2-Jan-10    1
3-Jan-10    1
4-Jan-10    1
5-Jan-10    1
6-Jan-10    1
7-Jan-10    1
8-Jan-10    2
9-Jan-10    2
10-Jan-10   2
11-Jan-10   2
12-Jan-10   2

a quick look at the calendar indicates that these values should be:

Date         Week
1-Jan-10    1
2-Jan-10    1
3-Jan-10    2
4-Jan-10    2
5-Jan-10    2
6-Jan-10    2
7-Jan-10    2
8-Jan-10    2
9-Jan-10    2
10-Jan-10    3
11-Jan-10    3
12-Jan-10    3

if I use the ‘iw’ switch instead of ‘ww’, the outcome is less desirable:

Date         Week
1-Jan-10    53
2-Jan-10    53
3-Jan-10    53
4-Jan-10    1
5-Jan-10    1
6-Jan-10    1
7-Jan-10    1
8-Jan-10    1
9-Jan-10    1
10-Jan-10   1
11-Jan-10   2
12-Jan-10   2

Is there another Oracle function that will calculate weeks as I would expect or do I need to write my own?

EDIT

I’m trying to match the logic used by Crystal Reports. Each full week starts on a Sunday; the first week of the year starts on whichever day is represented by January 1st (e.g. in 2010, January 1st is a Friday).

Answer 1

Based on this question, How do I calculate the week number given a date?, I wrote the following Oracle logic:

CASE
  --if [date field]'s day-of-week (e.g. Monday) is earlier than 1/1/YYYY's day-of-week
  WHEN to_char(to_date('01/01/' || to_char([date field],'YYYY'),'mm/dd/yyyy'), 'D') - to_char([date field], 'D') > 1 THEN
    --adjust the week
    trunc(to_char([date field], 'DDD') / 7) + 1 + 1 --'+ 1 + 1' used for clarity
  ELSE trunc(to_char([date field], 'DDD') / 7) + 1
END calendar_week