Question

I am using PHP. I want finish the jQuery AJAX process, (finish process and after data back to the main page) .

Then do the next jQuery thing. Any ideas on how to do it?

$.ajax({
  url: "page1.php", 
  dataType: "html",
  type: 'POST', 
  data: "value=" + value, 
  success: function(data){
    //some process
  }
});//ajax1
$.ajax({
  url: "page2.php", 
  dataType: "html",
  type: 'POST', 
  data: "value=" + value, 
  success: function(data){
    //some process
  }
});//ajax2
$.ajax({
  url: "page3.php", 
  dataType: "html",
  type: 'POST', 
  data: "value=" + value, 
  success: function(data){
    //some process
  }
});//ajax3

// finish all the 3 ajax process, do the below code
$(".page").css('display','block');

Answer 1

If you are using jQuery 1.5 or better, you can use the heavenly $.when construct, which uses the $.Deferred concept first implemented in that version of jQuery. You can run a function (or several functions) when all of several AJAX requests have completed.

So your code would look like this:

$.when($.ajax({
    url: "page1.php",
    dataType: "html",
    type: 'POST',
    data: "value=" + value,
    success: function (data) {
        //some process
    }
}), $.ajax({
    url: "page2.php",
    dataType: "html",
    type: 'POST',
    data: "value=" + value,
    success: function (data) {
        //some process
    }
}), $.ajax({
    url: "page3.php",
    dataType: "html",
    type: 'POST',
    data: "value=" + value,
    success: function (data) {
        //some process
    }
})).then(function () {

});