Question

I am using Play 1.2.5

I have a User model as below:

@Entity
public class User extends Model {
public String name;
public String city;
public String country;
public Integer zip;
}

The registration.html file is like this:

#{extends 'main.html' /}
#{set title:'Home' /}

<form action="@{Application.registerUser()}" method="get">
Name: <input type="text" name="txtName"><br>
City: <input type="text" name="txtCity"><br>
Country: <input type="text" name="txtCountry"><br>
Zip: <input type="text" name="txtZip"><br>
<input type="submit" value="Submit">
</form>

Below is the registerUser method in Application Controller:

public static void registerUser(String txtName,String txtCity,String txtCountry,Integer txtZip){
    //some business logic
    render();
}

The above signature works fine but I have to add a lot of parameters in the method which I dont want.

In a form, I have more than 15 fields, in such a case 15 parameters are too much!!!

Hence I need to know how to bind the user input values to a model (e.g. user model shown above) and pass it to the controller as an user object parameter to the method or as a map with key and value pairs (which ever is easier)?

Please let me know about this.

Regards,

Answer 1

Rename your input fields to user.name, user.city, etc., and change the controller method to

public static void registerUser(User user)

This is described in the documentation.