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Home/ Questions/Q 8692547
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T00:20:01+00:00 2026-06-13T00:20:01+00:00

I am using regex in perl to convert string to hex, however, when I

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I am using regex in perl to convert string to hex, however, when I do this, I get a warning from either perl critic or perl:

#$test is defined, i just put the regex code snippet here...
#this will trigger a warning from perl critic
#warning: use of regex expression without "/x" expression..
$text =~  s/(.)/sprintf("%x",ord($1))/eg;

#this will trigger a a warning at run time 
#warning: "uninitialized value $1 in regexp compilation"
$text =~   m{s/(.)/sprintf("%x",ord($1))/eg}x;

Is there a way to write the above code that doesn’t get a warning or feedback from Perl critic?

I think the issue is because ord is handling the undefined values, and when you put in /x then checking of the regex expression thinks that the value of $1 is invalid .

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  1. Editorial Team
    Editorial Team
    2026-06-13T00:20:01+00:00Added an answer on June 13, 2026 at 12:20 am

    This critic is what is called a false positive. There’s no need or reason for /x here. If you try to silence every critic, you’ll end up with weird code. That said, the critic was recommending

    s/(.)/sprintf("%x",ord($1))/exg
    

    Furthermore, it probably makes no sense to avoid converting newlines. If so, you want to use /s too.

    s/(.)/sprintf("%x",ord($1))/sexg
    
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