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Home/ Questions/Q 7900979
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T09:06:09+00:00 2026-06-03T09:06:09+00:00

I am using request.path to return the current URL in Django, and it is

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I am using request.path to return the current URL in Django, and it is returning /get/category.

I need it as get/category (without leading and trailing slash).

How can I do this?

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  1. Editorial Team
    Editorial Team
    2026-06-03T09:06:10+00:00Added an answer on June 3, 2026 at 9:06 am
    >>> "/get/category".strip("/")
    'get/category'
    

    strip() is the proper way to do this.

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