I am using scipy’s weave.inline to perform computationally expensive tasks. I have problems returning an one-dimensional array back into the python scope. Weave.inline uses a special argument called “return_val” for the purpose of returning values back into the python scope.
The following example returning an integer value works well:
>>> from scipy.weave import inline
>>> print inline(r'''int N = 10; return_val = N;''')
10
However the following example, which indeed compiles without prompting an error, does not return the array i would expect:
>>> from scipy.weave import inline
>>> code =\
r'''
int* pairs;
int lenght = 0;
for (int i=0;i<N;i++){
lenght += 1;
pairs = (int *)malloc(sizeof(int)*lenght);
pairs[i] = i;
std::cout << pairs[i] << std::endl;
}
return_val = pairs;
'''
>>> N = 5
>>> R = inline(code,['N'])
>>> print "RETURN_VAL:",R
0
1
2
3
4
RETURN_VAL: 1
I need to reallocate the size of the array “pairs” dynamically which is why I can’t pass a numpy.array or python list per se.
All you need to do is use the raw python c-api calls, or if you’re looking for something a bit more convenient, the built in scipy weave wrappers.
No guarantees about leaks or efficiency, but it should look something a bit like this: