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Editorial Team
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Asked: 2026-05-23T02:42:10+00:00

I am using Selenium 2 Java API with FirefoxDriver. When I fill a form,

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I am using Selenium 2 Java API with FirefoxDriver.
When I fill a form, checkboxes are added to the page depending the forms inputs.

I’d like to simulate a click on those checkboxes using Selenium.
The element are visible and usable in a regular browser but, selenium asserts that the elements are not visible.

"Element is not currently visible and so may not be interacted with"

Can I force selenium to ignore the non-visible state of the elements?
How can I force Selenium to interact with the non-visible element?

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1 Answer

  1. Editorial Team

    Selenium determines an element is visible or not by the following criteria (use a DOM inspector to determine what css applies to your element, make sure you look at computed style):

    • visibility != hidden
    • display != none (is also checked against every parent element)
    • opacity != 0 (this is not checked for clicking an element)
    • height and width are both > 0
    • for an input, the attribute type != hidden

    Your element is matching one of those criteria. If you do not have the ability to change the styling of the element, here is how you can forcefully do it with javascript (going to assume WebDriver since you said Selenium2 API):

    ((JavascriptExecutor)driver).executeScript("arguments[0].checked = true;", inputElement);

    But that won’t fire a javascript event, if you depend on the change event for that input you’ll have to fire it too (many ways to do that, easiest to use whatever javascript library is loaded on that page).

    The source for the visibility check –

    https://github.com/SeleniumHQ/selenium/blob/master/javascript/atoms/dom.js#L577

    The WebDriver spec that defines this –

    https://dvcs.w3.org/hg/webdriver/raw-file/tip/webdriver-spec.html#widl-WebElement-isDisplayed-boolean

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