Question

I am using sh shell script to read the files of a folder and display on the screen:

for d in `ls -1 $IMAGE_DIR | egrep "jpg$"`
do
  pgm_file=$IMAGE_DIR/`echo $d | sed 's/jpg$/pgm/'`

  echo "file  $pgm_file";
done

the output result is reading line by line:

file file1.jpg

file file2.jpg

file file3.jpg

file file4.jpg

Because I am not familiar with this language, I would like to have the result that print first 2 results in the same row like this:

file file1.jpg; file file2.jpg;

file file3.jpg; file file4.jpg;

In other languages, I just put d++ but it does not work with this case.

Would this be doable? I will be happy if you would provide me sample code.

thanks in advance.

Answer 1

Let the shell do more work for you:

end_of_line=""
for d in "$IMAGE_DIR"/*.jpg
do
  file=$( basename "$d" )
  printf "file %s; %s" "$file" "$end_of_line"
  if [[ -z "$end_of_line" ]]; then
    end_of_line=$'\n'
  else
    end_of_line=""
  fi

  pgm_file=${d%.jpg}.pgm
  # do something with "$pgm_file"
done