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I am using Socket communication in one of my Java applications.As I know if the program meets any abnormal termination the listening ports does not get closed and the program cannot be started back because it reports “Port already open..”
Do I have anyway to handle this problem? What is the general way used to handle this matter?
It sounds like your program is listening on a socket. Normally, when your program exits the OS closes all sockets that might be open (including listening sockets). However, for listening sockets the OS normally reserves the port for some time (several minutes) after your program exits so it can handle any outstanding connection attempts. You may notice that if you shut down your program abnormally, then come back some time later it will start up just fine.
If you want to avoid this delay time, you can use
setsockopt()to configure the socket with the SO_REUSEADDR option. This tells the OS that you know it’s OK to reuse the same address, and you won’t run into this problem.You can set this option in Java by using the
ServerSocket.setReuseAddress(true)method.