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Home/ Questions/Q 8723233
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T07:35:03+00:00 2026-06-13T07:35:03+00:00

I am using Spring Integration to make a POST REST WebService call My outbound

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I am using Spring Integration to make a POST REST WebService call
My outbound gateway is defined as below :

<int-http:outbound-gateway
        url="url"
        http-method="POST" request-channel="reqChannel"
        reply-channel="replyChannel" expected-response-type="java.lang.String">
</int-http:outbound-gateway>

My problem is with url. I need to have different url based on different conditions. How can I make the url variable configurable from payload rather than hard coding.

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  1. Editorial Team
    Editorial Team
    2026-06-13T07:35:04+00:00Added an answer on June 13, 2026 at 7:35 am

    You can use URI variables with expression(s) to replace placeholders in the URL…

    <outbound-gateway id="foo"
            url="http://localhost/{foo}/{bar}"
         ...
                        >
        <uri-variable name="foo" expression="headers['foo']"/>
        <uri-variable name="bar" expression="payload.bar"/>
    </outbound-gateway>
    
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