Question

I am using Spring Security 3.1 Active Directory.

I have a AD structure, where I need to get an OU value out of the AD structural distinguishedName attribute.

The OU that I want, will always be the first OU after the last DC.

below is my code example – I need to get the myCompany OU value, there must be a better way to do this:

public class Test {

public static void main(String[] args) {

    String s = "cn=harry,cn=group,ou=myCompany,ou=customers,dc=this,dc=that";

    System.out.println("s: "+s);

    String s1 = s.substring(s.indexOf("ou=") + 3);

    System.out.println("s1: "+s1);

    String s2 = s1.substring(s1.indexOf(""), s1.indexOf(",ou="));

    System.out.println("s2: "+s2);

}

}

This outputs the following:

s: cn=harry,ou=myCompany,ou=customers,dc=this,dc=that 
s1: myCompany,ou=customers,dc=this,dc=that 
s2: myCompany

Can anyone help please?

Answer 1

Regex! Pick your flavor below (first or second):

public static void main (String[] args){
     String s = "cn=harry,cn=group,ou=users,ou=myCompany,ou=customers,dc=this,dc=that";

     String first = s.replaceAll(".*?,ou=(.*?),.*", "$1");
     String middle = s.replaceAll(".*?,ou=.*?,ou=(.*?),.*", "$1");
     String third = s.replaceAll(".*,ou=(.*?),.*", "$1");

     System.out.println(first);
     System.out.println(middle);
     System.out.println(third);
}