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Home/ Questions/Q 499369
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T05:58:43+00:00 2026-05-13T05:58:43+00:00

I am using the below method between the 50lines of JQuery Code. From the

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I am using the below method between the 50lines of JQuery Code. From the Json Result, I have to do the Further process. What it does is, When first time it is not calling the specified url and debuuger not hit inside to the JSon. After all the below code runs then, It fetches the result and debugger(inside Json Method) is also hit. Could you explain me, In which way it is working. whether it is because of AJAX Call it is allowing next code to run before completing it.

var specExists = false;
url = '/CompanyAdd/SpecMathesWithProvAndContract'; debugger
$.getJSON(url, { OffId: OffID, CntId: CntID }, function(data) {
     debugger
     if (data) { debugger
     specExists = true;   
}   });

Thanks,
Nizam

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T05:58:43+00:00Added an answer on May 13, 2026 at 5:58 am

    The function(data) will only be called after the result was returned from the server. This is because that function is a callback function, meaning it will only execute after a JSON request is completed.

    So, in other words, when the Result is obtained, then Function(data) will be called.

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