Question

I am using the code

<?php
echo 'Hi';
$im = imagegrabscreen();
imagejpeg($im, "myscreenshot.jpg");
imagedestroy($im);
?>

This is creating a image myscreenshot.jpg with black background.But Iam expecting a jpeg image with white background and hi written on it

Answer 1

This is a common problem see ans you are getting this error because Apache is not allowed to interact with your desktop (Note)

Solution 1 : Apache Permission :

• Run the command services.msc as Admin.
• Find the Apache service in the list, right click and select Properties
• Click the Log On tab
• Change the service to use a local system account if it isn’t already
• Check the box that says Allow this service to interact with the desktop.
• Restart the Apache service.

Solution 2 : us using “boxcutter”

 $exec = exec('boxcutter -f image.png');

Solution 3 : Using COM seee ( http://php.net/manual/en/function.imagegrabwindow.php )

$browser = new COM("InternetExplorer.Application");
$handle = $browser->HWND;
$browser->Visible = true;
$browser->Navigate("http://stackoverflow.com"); // path to your URL 

/* Still working? */
while ($browser->Busy) {
    com_message_pump(4000);
}
$im = imagegrabwindow($handle, 0);
$browser->Quit();
imagepng($im, "myscreenshot.jpg");
imagedestroy($im);

I hope this helps