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Home/ Questions/Q 7671397
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T16:02:43+00:00 2026-05-31T16:02:43+00:00

I am using the csv python package to read a csv file like this:

  • 0

I am using the csv python package to read a csv file like this:

r = csv.DictReader(open(r'd:\aaa.csv', 'rb'))
for row in r:
  print row

The problem is that all the values in the resulting dictionary are strings and I need them to be converted to the respective types. I have a mapping between column names and the types.

Are there any shortcuts here or do I have to do it all myself?

EDIT

I have marked https://stackoverflow.com/a/9720733/80002 as the answer. Only, I have slightly modified it. There is no point to use DictReader if I am going to postprocess it anyway, so here is my modification of the Sven’s code:

r = csv.reader(open(r'd:\aaa.csv', 'rb'))
header = r.next()
converters = [converters_map[c] for c in header]
for row in r:
  row = {title:converter(value) for title, converter, value in zip(header, converters, row)}
  print row
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T16:02:45+00:00Added an answer on May 31, 2026 at 4:02 pm

    If you have a dictionary of converter functions converting strings to the respective types, then all you need is

    with open("d:/aaa.csv", "rb") as input_file:
        reader = csv.DictReader(input_file)
        for row in reader:
            row = {k: converters[k](v) for k, v in row.items()}
            print row
    

    (Python 2.7. For earlier versions use dict() instead of the dictionary comprehension.)

    You can wrap this code in a generator function (simply use yield row instead of print row).

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